- Homer’s mother has four children. Three of the children are named Spring, Summer, and Autumn. What is the name of the 4th child?
- A man tossed a baseball 20 feet. It stopped in mid-air, reversed directions and came back to him. How can this be explained?
- [An old classic!] A brick weighs 3 pounds plus half (the weight of) a brick. How much does a brick and a half weigh?
- Find three consecutive
*odd*integers which are all prime. - You have a string of 10 consecutive integers. The sum of the first three is 39. What is the sum of the last 3?
- If x#y = x + y +7, then what is the value of (2#3) # (7#0)?
- I have twice as many nickels as dimes. If the value of my nickels is $5.00, what is the value of my dimes?
- My neighbor has four daughters and each daughter has exactly one brother. How many children does my neighbor have?
- What is the largest integer you can square and get an answer less than 3000?
- 1/19 is to 1/17 as what number is to 95?
- In the first quarter of a game, the Denver Nuggets missed only 7 of their 25 field goal attempts. What was their scoring percentage for that quarter?
- Simplify this expression: (99 – 9) x (99 – 19) x (99 – 29) x . . . x (99 – 199).
- In my hand, I have two US coins whose total value is 55 cents, but one of the coins is not a nickel. What are the two coins?
- A frog is at the bottom of a 30-foot well. Each day he is able to jump up 5 ft, but during the nigth, he slides down 3 ft. How many days will it take him to jump out of the well?
- “Brothers and sisters have I none, but this man’s father is my father’s son.” To whom is the speaker referring?

**BONUSES**

**B1. ****Counterfeit Coin #4** * Another* new twist of Jan/Feb’s problems. I am now convinced this problem can be solved with

**up to 27**

**coins(!).**So pick your own number(s) and solve: You know one of them is counterfeit –

*and*that it is slightly heavier than the good coins, and you still have your balance scale. Determine the bad coin,

**still with**

**only 3****weighings**

*.*(A ‘weighing’ consists of coins being placed on both sides.)

**B2.** (see #4 above.) It turns out there is only one solution to #4 above. Why is that?

**B3. **(see #6 above.) If x&y = x # (y+7), then what is the value of (2#3) & (7#0)?

**B4. **(see #9 above.) Suppose we do not insist on an *integer* in #9 above. How (if any) does that change the answer?